courtneybcca
New member
Okay I need some help I think I got the answer but not sure
prove the lim as x approach 2 (-x^3 +1)=-7 using the epsilon-delta definition of the limit
so for every epsilon greater than zero there exists a delta greater than zero
0<lx-2l<delta then, l(-x^3 +1) +7l<epsilon
which works out to l-x^3 +8l<epsilon
when you do the graph I am getting delta: 1 as 2- cubed root of (8-epsilon) and delta: 2 as cube root of (8+epsilon) -2
Not sure how this relates
I was getting all this for my homework problems then the teacher gave us these problems and now I am lost... Grrr
prove the lim as x approach 2 (-x^3 +1)=-7 using the epsilon-delta definition of the limit
so for every epsilon greater than zero there exists a delta greater than zero
0<lx-2l<delta then, l(-x^3 +1) +7l<epsilon
which works out to l-x^3 +8l<epsilon
when you do the graph I am getting delta: 1 as 2- cubed root of (8-epsilon) and delta: 2 as cube root of (8+epsilon) -2
Not sure how this relates
I was getting all this for my homework problems then the teacher gave us these problems and now I am lost... Grrr