Calorie Question

[jenscats5]

Question:

I was reading a calculation where you multiply your weight into Kg then height into cm, etc add it all together with another number (655?) then multiply by X depending on how active you are to get cals needed per day to maintain your weight. (like 1.55 for moderately active)

Well, based on my current weight, I came up with 2,449 cals per day to maintain. So, if I have any less than that # I guess I'd lose weight?? Is that formula even accurate??

 

[Sassy69]

Can you post the equation or the ref it comes from? Did you convert all your units correctly?

 

[jenscats5]

Can you post the equation or the ref it comes from? Did you convert all your units correctly?

Here's the calculation:
1. Determine your weight in kg by dividing your weight in lbs by 2.2
(145/2.2 = 65.91)

2. Determine your height in centimeters by multiplying your height in inches by 2.54.
(5'4" = 64 x 2.54 = 162.56)

3. Complete the following equation:
655 + [9.6 x weight in kg] + [1.8 x height in cm] - [4.7 - age in years] = X

655 + 632.736 + 292.608 - 164.5 = 1415.844

4. Multiply X by one of the following activity factors:
Sedentary: 1.2
Slightly active: 1.375
Moderately active (moderate exercise 3-5 days/week): 1.55
Very active (strenuous exercise 6-7 days/week): 1.725

I think I'm somewhere between moderate & very active.....

So -- 1415.844 x 1.55 = 2194.5582 for moderate; 2442.3309 for very active

I think I messed up last nite..... but still, is this equation remotely accurate?? I would assume that if I'm below either of the above calories for the day, I'd lose weight??

 

[The Shadow]

Question:

I was reading a calculation where you multiply your weight into Kg then height into cm, etc add it all together with another number (655?) then multiply by X depending on how active you are to get cals needed per day to maintain your weight. (like 1.55 for moderately active)

Well, based on my current weight, I came up with 2,449 cals per day to maintain. So, if I have any less than that # I guess I'd lose weight?? Is that formula even accurate??

arent you ~120??



then 15x120 = approx main.

 

[jenscats5]

arent you ~120??



then 15x120 = approx main.

Nope, 145 in the am..... but I don't "look" 145, so to speak....

The calculation is supposed to be "maintenance" and was wondering what the validity the formula had as opposed to the weight x 12, 13, etc....

 

[The Shadow]

typicall womens bmr:


weight in kg times 0.9 times 12.......

 

[jenscats5]

typicall womens bmr:


weight in kg times 0.9 times 12.......

So, for me that's 711 -- what does that mean?

 

[The Shadow]

So, for me that's 711 -- what does that mean?

my fault...its times 24




so, 1400 cals is what you would burn lying at rest all day.......

 

[MsBeverlyHills]

how does that take into account lean body mass??? The # of maintance cals it gives you could be too little depending on how muscular you are.

 

[The Shadow]

how does that take into account lean body mass??? The # of maintance cals it gives you could be too little depending on how muscular you are.

it doesnt - thus the "typical" note