S samoth New member Jan 31, 2005 #69 y' + (1/2)y = 2 + t µ(t)y' + (1/2)µ(t)y = (2 + t)µ(t) µ(t) = e∫[p(t)dt] = et/2 et/2y' + (1/2)et/2y = 2et/2 + tet/2 d/dt[et/2y] = 2et/2 + tet/2 et/2y = ∫[2et/2 + tet/2]dt et/2y = 4et/2 + ∫[tet/2]dt
y' + (1/2)y = 2 + t µ(t)y' + (1/2)µ(t)y = (2 + t)µ(t) µ(t) = e∫[p(t)dt] = et/2 et/2y' + (1/2)et/2y = 2et/2 + tet/2 d/dt[et/2y] = 2et/2 + tet/2 et/2y = ∫[2et/2 + tet/2]dt et/2y = 4et/2 + ∫[tet/2]dt