Walmart looting = Reparations for Blacks

[gjohnson5]

LOL youre so pathetic.

Im sure we all feel sorry for his parents. Just let gjohnson be on his merry way living like the blind racist man he is.

Whatever 75th
OOH , I mean 0th...

Whenever you wanna have an in person debate, I'll be more then happy to verbally "beat your ass" in front of a crowd

 

[cobra108]

WELL i did not expect you to admit you hate blacks! you proved it already but I don't need you to actually admit it.

I'm not a biggot. Put it this way, I'm as much as a biggot as you are a retard.

 

[ziggyziggy]

I still think GJ is a good dude.

i agree. i have found many of his posts to be insightful and of value. this argument with me, however, is an exception to that rule.

Zig

 

[samoth]

If you wish to call something true , then prove it...
saying 2+2 = 5 does not make it "true"

Theorem: 2 + 2 = 5
Proof:
n(5n - 5) = n(5n - 5)
n(5n - 5) - n(5n - 5) = 0
(n - n)(5n - 5) = 0
5n(n - n) - 5(n - n) = 0
5n - 5 = 0
5n = 5
n + n = 5
or setting n = 2
2 + 2 = 5
QED

 

[samoth]

Sorry, it was too tempting....

 

[gjohnson5]

i agree. i have found many of his posts to be insightful and of value. this argument with me, however, is an exception to that rule.

Zig

That's kewl. I think that a "truth" is not a "thruth" until proven and I think webster's dictionary will verify this for me

 

[75th]

Whatever 75th
OOH , I mean 0th...

Whenever you wanna have an in person debate, I'll be more then happy to verbally "beat your ass" in front of a crowd

LOL. Verbally or physically, either way you wouldnt stand a chance.

 

[ziggyziggy]

Theorem: 2 + 2 = 5
Proof:
n(5n - 5) = n(5n - 5)
n(5n - 5) - n(5n - 5) = 0
(n - n)(5n - 5) = 0
5n(n - n) - 5(n - n) = 0
5n - 5 = 0
5n = 5
n + n = 5
or setting n = 2
2 + 2 = 5
QED

You, sir, have mad math skills. Having been a physicist at one point in my distant past, I giveth you props.

Having said that, though. Can you find a real-world application for your theorem?

Zig

 

[samoth]

Having said that, though. Can you find a real-world application for your theorem?

Sure can:

Theorem: All numbers are equal.
Proof:
Choose arbitrary a and b, and let t = a + b. Then
a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b

So all numbers are the same, and math is pointless.

 

[ziggyziggy]

Sure can:

Theorem: All numbers are equal.
Proof:
Choose arbitrary a and b, and let t = a + b. Then
a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b

So all numbers are the same, and math is pointless.

Thanks, my brain hurts now

Zig