Nerds needed- Enzyme Kinetics

[ziggyziggy]

drop the class

you're going to fail anyway

Bombs away, douchebag!

Zig

 

[Golemnium]

zz can you give me a hand? You said you know some of this stuff.

Tell me anything you can

 

[Tren_A_Sore]

lol

he doesn't know shit

myself on the other hand might know the answer, but I don't teach for free yo.

the only thing the zigmiester knows is how to insert a rat up his ass without the assitance of another person.


Can't we all just get along ?

 

[wootoom]

heres what you do you go down buy a gun point it at your head and do the a world a favor. pull the trigger

 

[ziggyziggy]

OK, for starters, you will need to graph Vi vs. . You will need to do this for the values with and with out the inhibitor. By looking at the graph with the inhibitor, you will be able to determine if it is comp or non-comp. That is the easy, no math part.

Now, as for calculating Vmax and Km, you will need to do a little algebra. Namely y = mx + b, using 1/ and 1/[Vi]. Easiest way to calculate 1/ and 1/[Vi] for each data pair is to use a calculator or Excell. I used Excell. When you plot 1/[Vi] on the y-axis vs. 1/ on the x-axis, you will end up with a straight line, instead of a parabola (graphs from paragraph will be parabolas). The slope of the line will be Km/Vmax, with the point where the y axis is crossed being 1/Vmax.

So, calculating the slope of the line using some of the data pairs is relatively easy. If you have 1/[Vi] on the y-axis and 1/ on the x-axis, then the data points will be in the format (x,y). For example, take data pair number three on the list, with no inhibitor. The data point for = 1, [Vi] = 0.69, can be expressed as (x,y) = (1 , 0.69). Taking this point, and converting it to (1/ , 1/[Vi]) would give you (x,y) = (1 , 1.449275362). Now, take the point ( , [Vi]) = (64 , 12.94). Converting this to (1/ , 1/[Vi]) gives you (x,y) = (0.015625 , 0.077279753).

Now, taking both of these (1/ , 1/[Vi]) data points, let's give them pair numbers. We will call the first pair (x2 , y2) and the second pair (x1 , y1). From these data points, the slope of the straight line between them, [Km]/[Vmax] can be determined by rise over run, or (y2-y1)/(x2-x1). In this case, that would be slope = (1.449275362 - 0.077279753) / (1 - 0.015625), this reduces to slope = (1.371995609) / (0.984375) = 1.393773317. This is [Km]/[Vmax]. Now that you know the slope of the line, [Km]/[Vmax], you can determine 1/[Vmax] using y = mx + b, where b is 1/ [Vmax], where the line crosses the y-axis at x=0.

In this case, I used Microsoft Excel, and the TREND function. I entered all 1/ values for x-values and all 1/[Vi] values for y-values. I then instructed Excel to find the y-value for x=0. This came out to be: 0.050020961. This is your 1/[Vmax] value. Therefore, [Vmax] = 19.99161893 or about 20. Since the slope of the line is [Km]/[Vmax], and we calculated it to be 1.393773317 in the last paragraph, we can use algebra to determine [Km]

slope = [Km] / [Vmax], so

[Km] = slope * [Vmax] = 1.393773317 * 19.99161893 = 27.86378503.

Again, this is for no substrate. I do not know what Ki, or he Michaelis-Menten and Eadie-Hofstee graphs are. If you can give me a bit more information, I may be able to help you with these too. Let me know if you have Excel, or another graphing program and are unfamiliar with its use.

Zig I'm just that good!

 

[ziggyziggy]

heres what you do you go down buy a gun point it at your head and do the a world a favor. pull the trigger

Better yet, if he doesn't have a gun, I will supply him with one.

Zig

 

[wootoom]

i wouldnt even help this waste of space

 

[ziggyziggy]

What can I say? I'm a geek at heart. I spent 2 years teaching physics to college kids after I got wounded. I love a challenge.

Zig

 

[ziggyziggy]

zz can you give me a hand? You said you know some of this stuff.

Tell me anything you can

C'mon you Wang, I'm waiting for you to sing my god-like math skills praises. On your knees, biotch!

Zig

 

[Golemnium]

Thanks a lot man. I wish I had some more power to my karma lol.