The problem calls for "an open box". I understand that to mean a box with only five sides of material; no material is used on the sixth side to seal the box.
The problem calls for "an open box". I understand that to mean a box with only five sides of material; no material is used on the sixth side to seal the box.
Ok...a buddy (aka Cheese for those who visit the Traning Board...hehe) came over for some Math help tonight. Of course...if it don't involve 10 fingers and 10 more toes...I'm lost and no help whatsoever!!!!
Was hoping that a few of the brains on this board could help with a few answers on a couple problems.
#3. 10 points
An open box is to be made by cutting equal squares for each corner of a 12-in square piece of cardboard and then folding up the sides. Find the length of the side of the square that must be cut out if the volume of the box is to be maximized.
What is the maximum volume?
#4. 8 points
The height of an object moving vertically is given by s=-16t^2 +96t+112 with "s" in feet and "t" in seconds. Find the following:
a. The time it takes the object to reach it maximum height.
b. The maximum height of the object.
#9. 10 points
Find the approximate area under the curve of y= (x)^(1/2), between x=1 and x=4, by dividing the indicated intervals into n=12 subintervals and then add up the areas of the inscribed rectangles.
I, as well as Cheese, appreciates any and all help on these problems. They are due on Tuesday morning at 8am. Thanks...!!!!!
Btw Bfold or Cheese, for #4 if you have a graphing calculator then you can graph that equation and trace the line that is graphed (with the trace feature or you can use the max/min feature that is on a lot of calcs.) and see what the max height is and what t would be there.
I'm not familiar with the term "OAC," but the difference here is not between two courses, it's the difference between an "A" and a "C" in the same course.
I'm not familiar with the term "OAC," but the difference here is not between two courses, it's the difference between an "A" and a "C" in the same course.