Suppose you toss 4 coins , what is the chance of getting two heads?

FORMULA; P=nCx p^x q^n-x
n= 4 (number of trials)
x= 2 (probabilty in q?)
p= 0.5 (probability of a head)
q= 0.5 ( 1-p)

P(2)= 4C2 (0.5)^2 (0.5)^2
=4!/2!/2! * 0.5^2*0.5^2
=.375
= 37.5% chance of getting two heads

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Suppose you toss 4 coins , what is the chance of getting two heads?

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huh..it's been a long time since anybody gave me HEAD.

A math/physics wiz at MIT this past year calculated the surface weights of a quarter. The absolute probability of heads over tails is something like 50.8...% vs 49.2...%. But the fact is the probability never changes.