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Author | Topic: Physics for today, Warick | ||
Guru ![]() ![]() ![]() ![]() ![]() Posts: 3100 |
Show tht the gravitational force on a test particle inside a thin spherical shell is zero. (a)By finding the force directly Hehehe, go to town Warick ![]() ![]() ![]() ![]() | ||
Amateur Bodybuilder ![]() ![]() Posts: 172 |
This will take him a while to respond to.... ------------------ ![]() ![]() ![]() ![]() | ||
Amateur Bodybuilder ![]() ![]() Posts: 78 |
I don't know how to formally prove that, but the Force on a test particle is equal to the product of its charge and the Electric Field (F = qE). The electric field is zero anywhere inside of a conductor (which I'm assuming that thin spherical shell is), so if E always equals zero, then so must F always equal zero. Sorry for the wussy answer, but I never liked electricity & magnetism much. =( -Warik ![]() ![]() ![]() | ||
Pro Bodybuilder ![]() ![]() ![]() Posts: 421 |
Wicket W. Warrick. ![]() ![]() ![]() ![]() | ||
Guru ![]() ![]() ![]() ![]() ![]() Posts: 3100 |
This deals with gravity specifically, no electrical charge involved. So, go from there using [bold]Fij[/bold]=Gmimj/r^2ij([bold]r[/bold]ij/rij), Sorry for the horrid equation, but there is no equation writer on here. Wait till I get my pc next week then I can hand write, scan and post. ![]() ![]() ![]() ![]() | ||
Guru ![]() ![]() ![]() ![]() ![]() Posts: 3100 |
come on there Warik, this is right up thy alley. ![]() ![]() ![]() ![]() | ||
Moderator ![]() ![]() ![]() ![]() Posts: 1165 |
that's a hard question chesty.. btw did you get mail? ![]() ![]() ![]() ![]() | ||
Guru ![]() ![]() ![]() ![]() ![]() Posts: 3100 |
Got it, just sent a reply, that is what me and someone else had figured, but weren't sure. ![]() ![]() ![]() ![]() | ||
Amateur Bodybuilder ![]() ![]() Posts: 78 |
Wait a minute, chesty, did you mean a test particle in the center of a thin spherical shell isolated from the rest of the universe? If so, then the gravitational force on the partical is obviously zero because if it is surrounded by a spherical shell, the force of gravity acting against it is equal from every single point surrounding it. The same applies for, say, a human being in the center of the Moon or something. The acceleration due to gravity would be zero. That, by the way, is probably the closest one can get to "zero gravity" because while floating around in a shuttle in space, one is still experiencing gravitational force from nearby celestial bodies and from the ship itself. Please don't tell me that you meant something else by your question. =) -Warik ![]() ![]() ![]() | ||
Guru ![]() ![]() ![]() ![]() ![]() Posts: 3100 |
Well, technically I did. I mean a test particle ANY WHERE in the sphere. Prove that it is zero. ![]() ![]() ![]() ![]() |
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