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Author Topic:   Physics for today, Warick
chesty

Guru

Posts: 3100
From:Everett, WA
Registered: Mar 2000

posted October 06, 2000 04:20 PM

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Show tht the gravitational force on a test particle inside a thin spherical shell is zero.

(a)By finding the force directly
(b)By showing that the gravitational potential is constant

Hehehe, go to town Warick


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superdave

Amateur Bodybuilder

Posts: 172
From:San Fernando Valley, circa 1977.
Registered: Sep 2000

posted October 06, 2000 05:02 PM

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This will take him a while to respond to....

------------------
Chesty/Dirk 2000


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Warik

Amateur Bodybuilder

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From:
Registered: Sep 2000

posted October 06, 2000 05:19 PM

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I don't know how to formally prove that, but the Force on a test particle is equal to the product of its charge and the Electric Field (F = qE). The electric field is zero anywhere inside of a conductor (which I'm assuming that thin spherical shell is), so if E always equals zero, then so must F always equal zero.

Sorry for the wussy answer, but I never liked electricity & magnetism much. =(

-Warik
(and spell my name right, damnit!)


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Weapon X

Pro Bodybuilder

Posts: 421
From:Earth, Milky Way Galaxy
Registered: Sep 2000

posted October 06, 2000 05:28 PM

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Wicket W. Warrick.


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chesty

Guru

Posts: 3100
From:Everett, WA
Registered: Mar 2000

posted October 06, 2000 05:30 PM

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This deals with gravity specifically, no electrical charge involved. So, go from there using [bold]Fij[/bold]=Gmimj/r^2ij([bold]r[/bold]ij/rij),

Sorry for the horrid equation, but there is no equation writer on here. Wait till I get my pc next week then I can hand write, scan and post.


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chesty

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Posts: 3100
From:Everett, WA
Registered: Mar 2000

posted October 07, 2000 12:27 PM

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come on there Warik, this is right up thy alley.


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JohnnyO

Moderator

Posts: 1165
From:Houston, TX, USA
Registered: Apr 2000

posted October 07, 2000 12:32 PM

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that's a hard question chesty.. btw did you get mail?


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chesty

Guru

Posts: 3100
From:Everett, WA
Registered: Mar 2000

posted October 07, 2000 12:46 PM

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Got it, just sent a reply, that is what me and someone else had figured, but weren't sure.


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Warik

Amateur Bodybuilder

Posts: 78
From:
Registered: Sep 2000

posted October 08, 2000 03:18 AM

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Wait a minute, chesty, did you mean a test particle in the center of a thin spherical shell isolated from the rest of the universe? If so, then the gravitational force on the partical is obviously zero because if it is surrounded by a spherical shell, the force of gravity acting against it is equal from every single point surrounding it. The same applies for, say, a human being in the center of the Moon or something. The acceleration due to gravity would be zero.

That, by the way, is probably the closest one can get to "zero gravity" because while floating around in a shuttle in space, one is still experiencing gravitational force from nearby celestial bodies and from the ship itself.

Please don't tell me that you meant something else by your question. =)

-Warik


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chesty

Guru

Posts: 3100
From:Everett, WA
Registered: Mar 2000

posted October 09, 2000 12:41 PM

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Well, technically I did. I mean a test particle ANY WHERE in the sphere. Prove that it is zero.


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